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Difficulty:
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Terrain:
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Size: 
(regular)
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This cache is a tribute to S10 for finding 1,000 geocaches. S10 is a pioneer and a leading figure in promoting geocaching in this area. His multi-caches (QCA series) were unequaled in time to complete and the distance you needed to travel as well as the number of parts you had to complete.
S10 always found a hiding spot that required bushwhacking. There weren’t too many of us that completed his extreme multi-caches. These caches have all been archived simply because they weren’t hunted and found very often. Thanks S10, for the hours of enjoyment I’ve had while seeking your caches of yesterday.
I attempted to imitate S10’s cache hiding style to honor his one-thousand cache finds.. I constructed what I believe to be a vintage S10 multi-cache and threw in a few extra steps. This cache can be done in a car, on a bicycle, on horseback or you may choose to walk. Its your choice. The cache container is an ammunition can painted silver.
Many of the numbers you collect on your journey will be converted using the following table:
1 | 2 | 3 | 4 | 5|
6 | 7 | 8 | 9 | 0|
Converting numbers using this table, a one converts to a six; a six converts to a one; a three to an eight; a zero to a five, etc.. (This is pretty much like the same system Geocaching.com uses in their encryption process.) After conversion, each number will be assigned a letter that will be used in the formula for finding the coordinates for the next part. Do be careful and check your work carefully!
All alphabetical characters you collect will be converted to numbers using A=1, B=2, C=3 etc., through Z=26.
I've added a worksheet to the listing. The sheet is in .jpg format and can be enlarged and printed. It should be helpful as you work your way through several variables.
Begin the hunt by going to the listed coordinates. Look north and locate the four-digit number. Convert these numbers using the chart. Converted, these numbers will equal A, B, C, and D.
Proceed to N41° 31. (A-B+C) (D-A+C) (D-C), W90° 35 . (D+C) (B+C) 9 where you can see a single neon lit digit (3). This number becomes E.
Proceed to N41° 30.1 (E) 5, W90° 38 . (2×E+1) (E+1) (2×E) where you will find a bronze plaque. Count the number of words in the plaque. Convert for that number to equal F.
Count the number of lines in the plaque. Convert that number to equal G.
Count the number of letters in the last line of the plaque. Convert that number to equal H.
After you do that, go to N41° 2 (G-F) . (G-F) (H) 8, W90° 3 G . (E) (G-H) (G) and find four numbers. Convert those numbers to find J, K, M and N.
Move on to N41° 27 . (2×K) (M-N) 0, W90° 44 . (M-J) 4 0. Once there you will be at the confluence of two streets, each with three-letter names. Convert those letters to numbers using the letter to number conversion method described above.
Add all six numbers to get a two-digit number. These two digits will equal P and Q.
Go to N41° 2 (Q-N) . (P-N) 2 2, W90° 46.004. There is a sign with information. Count the number of letters in the next to bottom line but do not count the C’s and the A’s. The number of letters (minus the Cs and A’s), will be a two digits number. Convert these two digits to get the values of R and S. (This is known as the EliWCoyote Correction, to be used again at a later date.)
Proceed to N41° 27 . R S 3, W90° 4 (R+N+C) . (B) 1 (S). There you will find a sign with three alpha-numeric characters. Convert the alpha characters to numbers using the letter to number conversion method described above.
Next, convert all four of these numbers using the number conversion table to get T, U, V and W.
Move along to N41° 2 (T) . (V-P+K) (V÷2) 1, W90° 4 (V+W) . (V) (V+W) 9. There is a four digit number on a sign. Convert these numbers to equal X, Y, Z and a. Note that “a” is a lowercase letter. Be careful!
The next part is at N41° 27 . (X) 3 8, W90° 5 (Y) . (Z) (X) 3, where you will find a sign with two (year) dates on it. Add these two dates together, then convert them using the number conversion chart. The resulting number will become (lower case) b, c, d and e.
Move to N41° 28.231, W90° (d-a) a . (b+c-e) 6 (b). Here you will find a sign with two digits. Multiply those two numbers and get a two digit number which will become f and g.
Proceed carefully to N41° 28 . (f) 3 0, W90° 5 (g-Y) . (f) (f+g) 0 and find a sign with a single digit. Convert that digit to becomes h.
Move to N41 2 (g+e-h) . (e-h) (a+h+E) 9, W90 52 . (a+e+h) (a-h) 3 and get the three two-digit numbers. Add them together and get the two-digit number that will become m and n.
You are now be positioning yourself to get the coordinates for the final silver painted cache. First, you must go to N41° 28.2 (n-a) 7, W90° 52. (m) (m-1) (n-a). At this location there is a plaque containing two names. You will must find the middle initial of both names. Convert these letters to numbers using the conversion table.
When you have done that, multiply those two numbers and assign the product p and q.
Congratulations! If you got this far you are on track to finish the S10 1000 cache. At the next stop you will find (with a bit of luck), the coordinates for the final cache. Those coordinates are located at: N41° (K) (2×E+1) . (p+q) (p+q-H) (q-p), W90° (g) (H) . (q÷2) (n) (h)
Additional Hints
(Decrypt)
Trg betnavmrq orsber lbh ortva