 Calculus 101
A cache by MATH_GUY Hidden: 3/30/2008
Size:  (Not chosen) Difficulty:  Terrain:  (1 is easiest, 5 is hardest)
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Calculus or not. You choose
The above coordinates are not the location of
the cache
The above coordinates are not the location of the cache Everyone
remembers there college calculus right? Well I remember how to
spell calculus. To get the Lat/Long for this cache you have to
determine the area under a line, hence calculus, i.e. integral
calculus. An integral is the fancy math way and easy if you can
remember how to do an integral and then evaluate it to determine
the area of any function. There is also the length times width
method if you have a square or rectangle or something that you can
break down into different shapes. There are two equations one for
latitude and one for longitude. The answer you get will be in the
DD.dddddd format not DD:MM.mmm format usually given. LATITUDE: take
the integral of 2X + 4, with respect to X, where X goes from zero
to 4.11234952. Or you can graph the equation y= 2x + 4 and
determine the area under the line. See the attached image of
theproblem. LATITUDE: Take the integral of 2X + 3, with respect to
X, where x goes from zero to 9.186389. Or you can graph the
equation y= 2x + 3 and determine the area under the line. See the
sketch of the problem.
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5 user(s) watching this cache.
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Additional Hints (Decrypt)
R-znvy zr sbe n uvag(Decrypted Hints)
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problem description
59 
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Current Time: 2/9/2010 11:39:54 PM (GMT-08:00) Pacific Time (US & Canada) (7:39 AM GMT)
Last Updated: 1/25/2010 10:13:01 AM (GMT-08:00) Pacific Time (US & Canada) (6:13 PM GMT)
Rendered: From Database
Coordinates are in the WGS84 datum
