Aoccdrnig to rscheearch, it deosn’t mttaer in waht oredr the ltteers in a wrod are, the olny iprmoatnt tihng is taht the frist and lsat ltteers be at the rghit pclae. The rset can be a toatl mses and you can sitll raed it wouthit porbelm. Tihs is bcuseae the huamn mnid deos not raed ervey lteter by istlef, but the wrod as a wlohe.
So, how aubot if the ltteers are rpleaecd wtih nmubres?
7H15 M3554G3 53RV35 7O PR0V3 H0W 0UR M1ND5 C4N D0 4M4Z1NG 7H1NG5! 1MPR3551V3 7H1NG5! 1N 7H3 B3G1NN1NG 17 WA5 H4RD BU7 N0W, 0N 7H15 LIN3 Y0UR M1ND 1S R34D1NG 17 4U70M471C4LLY W17H 0U7 3V3N 7H1NK1NG 4B0U7 17. 0NLY C3R741N P30PL3 C4N R3AD 7H15.
4nÐ h3r3 1$ ¥37 4n07h3r v3r$10n 0ƒ ƒ19µr471v3 $p33(h: £337.
╫0\/\/, /-\8[]µ† 7`|-|1$? c/-\|\| U F|9uR3 0u7 \/\/╫/-\7 |7 5/-\'/$?
7`|-|1$ 1$ /-\|\| 3><7`R3|\/|3 √3R$10|\| 0|= 1337 $|o3/-\|< .
h3r3 ¥0µ w1££ ƒ1nÐ 7h3 (00rÐ1n473$ m1x3Ð 1n 4m0n9 7h3 73x7. 7h€ £0ç@7¡0n ƒ0r wh@7 ¥0µ
§€€k (4n b3 ƒ0µnÐ b3£0w m1x3Ð 1n 4m0n9 7h3 w0rÐ$ 0ƒ 7h3 Pr34mb£3 70 7h3 µn173Ð $7473$ (0n$717µ710n.
You can validate your puzzle solution with certitude.
(0n9r47µ£4710n$ 70 4n0n¥m1k37 0n ƒ7ƒ h0n0r$!!
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