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Despres Bonus Mystery Cache

Hidden : 4/20/2022
Difficulty:
3 out of 5
Terrain:
2 out of 5

Size: Size:   other (other)

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Geocache Description:


In 2020 the Town of Westborough purchased the "Despres Property", a total of 66 acres.  It is an IDEAL location for a series of Geocaches.  

After you find all seven regular caches, you can use the clues provided to find the BONUS mystery cache.  See the description here for the details.  We recommend that you look there before you start on any cache.   These caches are placed by Diamond-JB and Gold_BB, Grandfather and Grandson.

On December 14, 2021, we appeared before the Westborough Conservation Commission and after we explained our project, they voted to approve our placement of these caches.

Here are the rules for finding this bonus cache.  As you're finding each of the Despres Caches #1 - #7, note the color of the cache container.  Those colors are converted into letters that will aid you in finding this bonus.

The bonus cache is located at  N42 14.ABC, W 71 37.DEF

The color of Despres #1 defines symbol  Alpha:  Pink = 0, Gold = 1,  Black = 2, Blue/Purple = 3, Brown =4, Gray = 5, Red= 6

The color of Despres #2 defines symbol  Beta:  Clear = 0, Black = 1,  Gold = 2, Red =3, Blue/Purple = 4,  Green = 5, Brown = 6 

The color of Despres #3 defines symbol  Gamma:  Black = 0, Green = 1,  Brown = 2, Red =3, Orange = 4,  Yellow = 5, Pink = 6 

The color of Despres #4 defines symbol  Delta:  Gold = 0, Brown = 1,  Green = 2, Red =3, Yellow = 4,  Clear = 5, Black = 6 

The color of Despres #5 defines symbol  Epsilon:  Green = 0, Black = 1,  Gold = 2, Red =3, Blue/Purple = 4,  Yellow = 5, Gray = 6 

The color of Despres #6 defines symbol  Zeta:  Yellow = 0, Black = 1,  Gold = 2, Pink = 3, Blue/Purple = 4,  Clear = 5, Brown = 6 

The color of Despres #7 defines symbol  Eta:  Green = 0, Black = 1,  Gold = 2, Red =3, Blue/Purple = 4,  Clear = 5, Gray = 6 

Note:  The symbol "mod" in the following equations means "Take the remainder after dividing the quantity in parenthesis by 10".

So mod(17) = 7, and mod(33) = 3.

A = mod(Alpha + Beta + Gamma + Delta  + Epsilon + Zeta + Eta + 5)

B = mod(Alpha + Beta + Gamma - Delta + Epsilon - Zeta + Eta + 8)

C = mod(-Alpha - Beta + Gamma + Delta + Epsilon +Zeta + Eta - 3)

D = mod(Alpha + Beta + Gamma - Delta + Epsilon + Zeta - Eta

E = mod(Alpha - Beta - Gamma + Delta - Epsilon + Zeta + Eta + 4)

F = mod(-Alpha + Beta + Gamma + Delta + Epsilon - Zeta + Eta + 5)

Additional Hints (No hints available.)