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BoB VII - Szabadság-híd

A cache by TeamGBGA Send Message to Owner Message this owner
Hidden : 01/22/2010
Difficulty:
1.5 out of 5
Terrain:
1.5 out of 5

Size: Size: micro (micro)

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Geocache Description:

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This is the seventh part of a bridges series located in Budapest. All of them will be MultiCaches with just a few stages. Please keep the determined variables. They will be useful for an additional 'bonus'-cache.



Bridges Of Budapest

Liberty Bridge - Szabadság-híd

The Szabadság híd or Liberty Bridge (sometimes Freedom Bridge) in Budapest, Hungary, connects Buda and Pest across the River Danube. It is the third southernmost public road bridge in Budapest, located at the southern end of the City Centre.
At its two ends are:
* Gellért tér (at the foot of Gellért Hill, with the Gellért Spa and Hotel Gellért) and
* Fovám tér (with the Great Market Hall and the nearby Budapest University of Economics).

The bridge was built between 1894 and 1896 to the plans of János Feketeházy. Although radically different in structure, the bridge imitates the general outline of a chain-type bridge, which was considered an aesthetically preferable form at the time of construction. The bridge was opened in the presence of Emperor Franz Joseph; the last silver rivet on the Pest abutment was inserted into the iron structure by the Emperor himself, and the bridge was originally named after him.
It is 333.6 m in length and 20.1 m in width. The top of the four masts are decorated with large bronze statues of the Turul, a falcon-like bird, prominent in ancient Hungarian mythology.

Many trams used to cross the twin-road bridge, which was also heavily burdened with car traffic, and there is an initiative to convert it to a pedestrian-only crossing once the fourth underground metro line is completed in Budapest in the coming decade.
Start:
Look for a black memorial tablet when arriving at the header-coordinates.
There are interesting facts on it.
You can find a 2 digit number on it, call it 'K'

Cache: (updated formula)
N 47° xx,xxx' xx,xxx=N0+(K*2+2)/1000
E 019° yy,yyy' yy,yyy=E0+(K*3+36)/1000

Happy caching!

     TeamGBGA


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