A 100g geocache is suspended by 30lb fishing line, 15m up at the midway point between two beech trees, 1 and 2, which are 15.192m apart.
A geocacher weighing 70kg and carrying 5kg of climbing gear climbs Tree 1 with Rope A and attaches another rope (Rope B) to a sturdy anchor point. Using a throwline, he sends the standing end of Rope B over a limb in Tree 2, descends Tree 1, ascends Tree 2, and secures Rope B to a sturdy anchor point, creating a straight line of horizontal rope between Trees 1 and 2. Assume no tension in Rope B at this point. Assume the anchor points are the same distance apart as the trees.
The geocacher clips to Rope B with a small pulley, and pulls himself out to the centre of Rope B, causing it to deflect downwards in the middle a distance of 1m.
Using the table below (where "angle" refers to the angle created in the rope by the pulley) and the formula calculate the force in kilograms on just one anchor point using the formula:
F = w x (% ratio / 100) Where F is the force on one anchor point and w is the weight of the load.
Calculate your answer to three decimal places. ABC.DEG
The cache can be found at N 50 [D][G-E].[C+A][G+E][B-C] W 003 [D][D-A].[A+E]B[DxE]
You can check your answers for this puzzle on GeoChecker.com.
Do not attempt this cache without:
- A climbing buddy
- Sufficient rope to climb and build a bridge
- A tensioning system
- A harness
- A helmet
- A pen, though there is a pencil in the pot on placement
Nobody - not me, not geocaching.com, not your lucky pants - is responsible for your safety apart from YOU. Do not attempt if you are at all unsure. No part of this description is intended to provide any guidance or instruction whatsoever. Make sure you are personally competent to complete this challenge.
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