Around Launton-1 Traditional Cache
terita: Archived as is the series due to proximity of a new Old folks home.
Please note Use of geocaching.com services is subject to the terms and conditions
in our disclaimer.
This 4 part cache series is a little trial for my next planned and larger multi. There is a log in each of the caches.
The series shouldn't take more than a couple hours to complete.
This one, part 1 is a simple, no frills traditional cache.
Inside you will find 2 sets of coordinates for parts 2 and 3 respectively. These are simple puzzles but you may need the information below to solve them.
In each of these 2 caches (2 & 3) there are part co-ordinates that will lead you to the final “multi” cache.
You are looking for a small cache containing a 35mm film canister, log but no pen. The co-ordinates for part's 2 & 3 are in the 35mm canister.
Part 2 GC12RTA
Part 3 GC12RTD
Final GC12R86
Bonus Cache GC12RCH
++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++
The Binary System
If you are conversant with this system then read no more and off you go to grab the cache(s)
If you are unfamiliar or just a bit rusty, then please read on.
The Binary numbering system is a very basic system and is the foundation for computer systems worldwide. It uses only the digits “1” and “0”
These two digits are placed in number strings and the position of the “1” digit determine it’s value. “0” has no value.
Starting from right to left, the value of each digit is doubled as shown below.
You could of course go on doubling up the numbers forever but that gets very complicated and there are much more advanced numbering systems to cope with the bigger numbers.
512 - 256 - 128 - 64 - 32 - 16 - 8 - 4 - 2 - 1
By adding the corresponding digits together we finish up with a standard (base 10) number.
E.G.
The binary number 1001100110 = 614. i.e.512+64+32+4+2
Or
110011 = 51. i.e. 32+16+2+1
With these 10 digits you can add up to a maximum of 1023, quite enough for our purposes.
Anyway that’s all there is to it. Just remember that the binary system will not give you any preceding zero’s so where necessary, you will have to add them yourself.
You boffins still here?
So
N 45.36.844 E 020.46.047 =
N 101101.100100.1101001100 E 10100.101110.101111
Get it ?
Practice then.
Decode this
N 110011.110001.101111010 W 1.1111.1111011000.
N -- . -- . --- W --- . -- . ---
You should get >>>>>> Clue 1
Success, good and that’s all you need to know to complete this short series.
Good luck and thank you for taking part
Additional Hints
(Decrypt)
[Clue 1] Abegu svir bar.sbhe avar.guerr frira rvtug
Jrfg bar.bar svir.avar rvtug sbhe
[Clue 2] Haqre fbzr ehooyr va gur onfr bs n gerr.
Treasures
You'll collect a digital Treasure from one of these collections when you find and log this geocache:
Loading Treasures