The listed coordinates are not the
position of the cache. You must solve the position of the cache
from the description below.
This year is special because it contains two palindrome calendar
dates: Jan. 10, 2011 expressed as 1-10-2011 (or simply 1102011) and
Nov. 2, 2011 written as 11-02-2011 (11022011). The first one has
already occurred and the second one, 11022011, is coming up. (Note
that in most of the world where day-month-year date format is used,
this year also has two palindrome dates. Date 11022011 representing
11 February 2011 already passed and 1102011 corresponding to 1
October 2011 is about to occur.)
After 2011, there will be one more year in this (21st) century
containing two palindrome dates. That will be 2021, with palindrome
dates Jan. 20, 2021 (1202021) and Dec. 2, 2021 (12022021). (In the
rest of the world, after 2011, there will also be one more year in
this century containing two palindrome dates, but that year will be
2012 instead of 2021.)
Nov. 2, 2011 represented as 11022011 is a one-of-a-kind
palindrome date with respect to all palindrome dates contained in
all four-digit years. Why?
First, number 11022011 equals 7 x 7 x 11 x 11 x 11 x 13 x 13,
that is, the product of seven square, eleven cube and thirteen
square where numbers seven, eleven and thirteen are three
consecutive prime numbers! So, number 11022011 is divisible by the
product of the squares of three consecutive prime numbers!
Furthermore, it's also divisible by the cube of the middle prime of
the three consecutive primes! In fact, 11022011 = 72 x
113 x 132 where, interestingly enough, the
three superscripts side-by-side constitute 232 which is also a
palindrome! Fascinating, isn't it? No other such palindrome date
exists in all four-digit years.
In addition, since 7 x 11 x 13 yields 1001, another palindrome
number, one could also express date 11022011 as 1001 x 11 x 1001
where the left and right sides of this expression divided in the
middle are almost mirror images of one another! Isn't that
something?
Also, if date number 11022011 is split into four two-digit
numbers as 11, 02, 20 and 11, the first two numbers add up to 13
and the sum of the last two is 31, and 13 and 31 put side-by-side
yield 1331 = 11 x 11 x 11! Now, by introducing two zeros in-between
the digits of the first and last elevens, this expression will
change from 11 x 11 x 11 to 1001 x 11 x 1001 = 11022011! Wow!
I hope this article convinces you that the second palindrome
date of this year 11022011 is indeed special and unique compared to
all other palindrome dates in four-digit years. And aren't we lucky
that it is going to occur in our lifetime?
Original article written by Dr. Aziz Inan (pictured above),
Professor of Electrical Engineering at the University of
Portland.
Cache is hidden using the original coordinates and
adding the year to the North coordinates and the month and day to
the West coordinates.
You can check your answers for this puzzle on
Geochecker.com.