Für Mathematiker Mystery Cache

This cache has been archived.

50Hz: Der Jägerstand ist am Ende, das Versteck ebenso, deshalb ist es auch mit dem Cache zu Ende

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Hidden : 2/2/2013
Difficulty:
5 out of 5
Terrain:
1.5 out of 5

Size: Size: small (small)

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Geocache Description:

Da neben der Dose ein Jägerstand ist, bitte nicht in der Dämmerung kommen.

AA=0
AB=T/PI
AC=T/2/PI
AD=-T/PI+2
AE=1
AF=T/PI
AG=T/11*1.669+2
AH=(T/9+0.5)*1.669
AI=T/5*1.669+2
AJ=0.5*1.669
AK=0.7*1.669+2
AL=T/7*1.669
AM=sin(T)/2*(2/1.8)+5.097
AN=(cos(T)/2+0.5)*(2/1.8)
AO=sin(T)/2.5*(2/1.8)+5.097
AP=(cos(T)/2.5+1/2.5+1)*(2/1.8)
AQ=(cos(T/2)/2+0.5+0.5)*(2/1.5)+6.197
AR=(sin(T/2)/2+1)*(2/1.5)
AS=(T/(2*PI)+0.5)*(2/1.5)+6.197
AT=T/(2*PI)*(2/1.5)
AU=(T/(1.6*PI)+0.5)*(2/1.5)+6.197
AV=0
AW=sin(T)/2*(2/1.8)+9.347
AX=(cos(T)/2+0.5)*(2/1.8)
AY=sin(T)/2.5*(2/1.8)+9.347
AZ=(cos(T)/2.5+1/2.5+1)*(2/1.8)

BA=T/(3.25*PI)-0.387+11.457
BB=T/PI
BC=-T/(2.17*PI)+0.6-0.387+11.457
BD=2
BE=-T/(2.17*PI)+0.8-0.387+11.457
BF=1
BG=(sin(T)/2+0.5)*(2/1.5)+12.05
BH=(cos(T)/2+0.5)*(2/1.5)
BI=(sin(T/(-4))+1)*(2/1.5)+12.05
BJ=(cos(T/(-4))+0.5)*(2/1.5)
BK=sin(T)/2*(2/1.8)+0.5+13.7
BL=(cos(T)/2+0.5)*(2/1.8)
BM=sin(T)/2.5*(2/1.8)+0.5+13.7
BN=(cos(T)/2.5+1/2.5+1)*(2/1.8)
BO=0
BP=T/PI-2.5
BQ=T/(2*PI)
BR=0-2.5
BS=T/(3.25*PI)
BT=1-2.5
BU=T/(2*PI)
BV=2-2.5
BW=sin(T)/1.2+0.5+0.333+2
BX=cos(T)+1-2.5
BY=(sin(T)/2)*(2/1.5)+0.5+4.45
BZ=(cos(T)/2+1)*(2/1.5)-2.5

CA=(sin(T/4+PI/2)-0.5)*(2/1.5)+0.5+4.45
CB=(cos(T/4+PI/2)+1)*(2/1.5)-2.5
CC=(sin(T/2)/2)*(2/1.8)+6.666
CD=(cos(T/2)/2+0.5)*(2/1.8)-2.5
CE=(0)*(2/1.8)+6.666
CF=(T/25*PI+1)*(2/1.8)-2.5
CG=(T/(3.25*PI))*(2/1.8)+6.666
CH=(1.8)*(2/1.8)-2.5
CI=(sin(T)/2+0.5)*(2/1.5)+7.733
CJ=(cos(T)/2+0.5)*(2/1.5)-2.5
CK=(sin(T/(-4))+1)*(2/1.5)+7.733
CL=(cos(T/(-4))+0.5)*(2/1.5)-2.5
CM=(sin(T)/2+0.5)*(2/1.8)+10
CN=(cos(T)/2+0.5)*(2/1.8)-2.5
CO=(sin(T)/2.5+0.5)*(2/1.8)+10
CP=(cos(T)/2.5+1/2.5+1)*(2/1.8)-2.5
CQ=(cos(T/2)/2+0.5+0.5)*(2/1.5)+10.8
CR=(sin(T/2)/2+1)*(2/1.5)-2.5
CS=(T/(2*PI)+0.5)*(2/1.5)+10.8
CT=T/(2*PI)*(2/1.5)-2.5
CU=(T/(1.6*PI)+0.5)*(2/1.5)+10.8
CV=-2.5
CW=(T/11)*(2/1.2)+13.3
CX=(T/9+0.5)*(2/1.2)-2.5
CY=(T/5)*(2/1.2)+13.3
CZ=(0.5)*(2/1.2)-2.5

DA=(0.7)*(2/1.2)+13.3
DB=(T/7)*(2/1.2)-2.5

Additional Hints (Decrypt)

cnnejrvfr shaxgvbavregf Onhzfghzcs

Decryption Key

A|B|C|D|E|F|G|H|I|J|K|L|M
-------------------------
N|O|P|Q|R|S|T|U|V|W|X|Y|Z

(letter above equals below, and vice versa)


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