The cache is at:
N 53 {A} (A+C) . (A+D) (E-(D+A)) (E-D-B-A)
W 002 (C-A) (B+C) . ((D/C)+(B-A)) ((CD/(A/B))/(F/B)) (G/(E/B))
The cache coordinate can be established by substituting the letters with the correct numerical value and then doing a bit of basic maths. If the letters are within {} then it is a stright substitution of the number, if within () then do the maths.
Method 1:
Guessing the values for each letter. Not very logical but hey, you may get lucky!
Method 2:
Work out the values for each letter using algebra. Not as hard as it might first look. Now for this method you will need some more information, so I will give you the values for A and B.
A = 1
B = 2
Now, to make it really easy peasy the rest of the numbers are in an infinite geometric sequence.
C = D/B
D = 2*{B} + C
Method 3:
Come on! I've already made it so easy, what to you want me to do, just give you the answer?
Oh well, I tried to make it easy peasy for those who don't like complicated puzzles. But yes if you really are stuck I will give you the answer. Now is it really that hard to solve?
The cache is a very small disguised tube.
