The puzzle
If we list all the natural numbers below 10 that are divisible by 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.
Define f(n) as the sum of the multiples of 3 and 5 which are less than n. Thus we can write:
f(10) = 23.
N = f(4720) + f(240) + f(77),
E = f(175) + f(10).
Geochecker
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If you would like to help extend this series please contact mjouk.