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Genius Mystery Cache

This cache has been archived.

SoulDrifters: Time to let this one go.
Thanks to all who found it!

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Hidden : 9/18/2014
Difficulty:
2 out of 5
Terrain:
2 out of 5

Size: Size:   small (small)

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Geocache Description:


Genius

To find this cache you will need to look at these sums:

  \begin{displaymath} \lim_{\epsilon \to 0} {w_2 - w_1 \over \epsilon^2} = R(u,v)w \end{displaymath} S  \begin{displaymath}R(u,v)w = R^\alpha_{\beta\gamma\delta} u^\beta v^\gamma w^\delta,\end{displaymath} 2   \begin{displaymath} \lim_{\epsilon \to 0} {w_2 - w_1 \over \epsilon^2} = R(u,v)w \end{displaymath} 9

\begin{displaymath}R(u,v)w = R^\alpha_{\beta\gamma\delta} u^\beta v^\gamma w^\delta,\end{displaymath} 4 \begin{displaymath}\lim_{\epsilon \to 0} {v_2 - v_1 \over \epsilon^2} = R(u,v)v,\end{displaymath} 9 \begin{displaymath}\lim_{\epsilon \to 0} {a^\alpha \over \epsilon} = - R^\alpha_{\beta\gamma\delta} v^\beta u^\gamma v^\delta . \end{displaymath}.

\begin{displaymath}\lim_{V \to 0} {\ddot V\over V} \Bigr\vert _{t = 0} = - R_{\beta\delta} v^\beta v^\delta .\end{displaymath} 3 \begin{displaymath}\lim_{V \to 0} {\ddot V\over V}\Bigr\vert _{t = 0} = - R^\alpha_{\beta\alpha\delta} v^\beta v^\delta .\end{displaymath} 6 \begin{displaymath}R_{\alpha \beta} = T_{\alpha \beta} - {1\over 2}g_{\alpha \beta} T^\gamma_\gamma . \end{displaymath} 6

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G_{\mu\nu} = R_{\mu\nu} + (\Lambda - {1 \over 2}R) g_{\mu\nu} E \begin{displaymath}R_{\alpha \beta} = T_{\alpha \beta} - {1\over 2}g_{\alpha \beta} T^\gamma_\gamma . \end{displaymath} 3 \begin{displaymath}R^\alpha_\alpha - {1\over 2}g^\alpha_\alpha R^\gamma_\gamma = T^\alpha_\alpha, \end{displaymath} 0\begin{displaymath}R(u,v)w = R^\alpha_{\beta\gamma\delta} u^\beta v^\gamma w^\delta,\end{displaymath} 4 \begin{displaymath}R_{tt} = T_{tt} - {1\over 2}g_{tt} T^\gamma_\gamma \end{displaymath} 6 \begin{displaymath}R(u,v)w = R^\alpha_{\beta\gamma\delta} u^\beta v^\gamma w^\delta,\end{displaymath} .\begin{displaymath}\lim_{\epsilon \to 0} {v_2 - v_1 \over \epsilon^2} = R(u,v)v,\end{displaymath} 3 \begin{displaymath}R(u,v)w = R^\alpha_{\beta\gamma\delta} u^\beta v^\gamma w^\delta,\end{displaymath} 0 \begin{displaymath}\lim_{\epsilon \to 0} {a \over \epsilon} = R(u,v)v . \end{displaymath} 1

 

 

Hope you enjoy the cache.

 

http://1.bp.blogspot.com/-pvoHe8EABpg/UYjbFxjXd5I/AAAAAAAACMc/Du5-D1Ij6sA/s1600/einstein.jpg

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