Note: due to the final cache getting muggled twice in a row I've moved the final location. The clues remain the same.
As a Scout leader at Glenfield Scouts I was happy in April 2014 when the new 'Geocaching Activity Badge' was released. We began it in May 2014, finding the required standard caches was achievable given the nearby caches placed by 'SSouter' (originally 5 of these were on the route but I think some have gone to be replaced with at least one new one) but finding a 'Multi' was not so easy. So I decided to create one around Glenfield village. I've received permission from Glenfield Parish Council to place the cache in the final location so thank you to all who helped to arrange that.
Congratulations to BD1234 & rr300tdi for FTF!
The clues aren't too difficult and the walk is only 1.75 miles on tarmaced surface. The coordinates take you to a car park where you can start. (and this is close to the final cache position!)
You can check your coordinates here.. (updated for revised coordinates) GeoChecker.com.
- STAGE 1 N 52° 38.902 W 001° 12.241
What is the maximum time you can park for? (Bare this in mind if you've parked in the car park!)
a = Maximum Time (in hours)
- STAGE 2 N 52° 38.985 W 001° 12.313
After how long can you return to the parking space?
b = Time (in hours)
- STAGE 3 N 52° 38.993 W 001° 12.487
What is the 6th digit of the phone number (2nd digit after area code)?
c = 6th digit of the phone number
- STAGE 4 N 52° 39.154 W 001° 12.300
What is the numbr of upright vertical bars on the left hand (North) railings?
d = Number of vertical bars
- STAGE 5 N 52° 39.229 W 001° 11.959
What number is on the Right hand side of the post (single digit the same as one on left hand side)?
e = Number on Right hand side of post
- STAGE 6 N 52° 39.063 W 001° 12.204
What number is on the lamp post?
f = Number on lamp post
- STAGE 7 N 52° 38.858 W 001° 12.220
What number is on the zebra crossing beacon on the right (South)?
g = Number on beacon
Now the final cache is located at:
N 52° e h . c e g W 001° b i . e j h
Where:
h = f - b - d
i = e - b
j= c - b