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La Pythie à BD Mystery Cache

Hidden : 1/11/2015
Difficulty:
3.5 out of 5
Terrain:
2 out of 5

Size: Size:   micro (micro)

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Geocache Description:

La Pythie pourrait vous aider à résoudre cette mystery. 

Enigme faisant suite à une mauvaise expérience professionnelle ... (extrait) : 


select p, d, t, q, c, s, h, n from (
select * from (
with wt1 as (select 'n' p,3 d,7 t,4 q,5 c, 6 s, 1 h, 1 n from dual),
wt2 as (select 'e' p,9 d,6 t,7 q,1 c, 0 s, 3 h, 4 n  from dual)
select case when t1.p = t6.p then t1.p else wt2.p end p,
decode(wt1.d, t1.d, t7.n, t2.c, t4.s, t6.t, t7.d, t8.c) d,
max(greatest(t2.d, t6.q, t7.c, t8.h, t5.n, t1.s, t1.d, t2.q, t7.h)) t,
min(least(t4.c, t5.d, t8.h, wt2.n, t4.s, t1.c, t7.s, t5.d)) q,
decode(sign(t2.q-t4.d), -1, t4.q, decode(sign(t8.n-t3.s), -1, t2.n, decode(sign(t2.t-t4.h), 0, t2.h, t5.c))) c,
case when exists (
        select 1
        from wt1, wt2
        where wt1.t = wt2.q
    ) then wt1.n else wt2.d end s,
    to_number(substr(concat(t5.d, t6.h) || t3.d || concat(t7.s, t1.q) || substr(concat(t8.d, t3.s) || t7.c * t3.c * t4.s, -4,1),-1,1)) h,
    to_number(substr((replace(replace(to_char((t3.h * t4.t * t6.c + t2.d + t1.h * t8.q * (t6.n * (to_date('01/01/2017', 'dd/mm/yyyy')-to_date('01/01/2016', 'dd/mm/yyyy'))))), '3', '9'), '9', '4'))*3, -1,1)) n,
0 r
from 
(select 'n' p,4 d,3 t,0 q,9 c, 3 s, 1 h, 3 n from dual) t1,
(select 'e' p,4 d,2 t,4 q,3 c, 2 s, 6 h, 7 n  from dual) t2,
(select 'e' p,6 d,6 t,5 q,9 c, 7 s, 4 h, 1 n  from dual) t3,
(select 'n' p,1 d,8 t,1 q,4 c, 4 s, 2 h, 9 n  from dual) t4,
(select 'e' p,6 d,9 t,3 q,6 c, 3 s, 1 h, 0 n  from dual) t5,
(select 'n' p,9 d,4 t,4 q,3 c, 1 s, 9 h, 4 n  from dual) t6,
(select 'n' p,4 d,1 t,3 q,8 c, 5 s, 3 h, 3 n  from dual) t7,
(select 'e' p,1 d,9 t,4 q,0 c, 7 s, 7 h, 2 n  from dual) t8,
wt1, wt2
group by case when t1.p = t6.p then t1.p else wt2.p end ,
decode(wt1.d, t1.d, t7.n, t2.c, t4.s, t6.t, t7.d, t8.c) ,
decode(sign(t2.q-t4.d), -1, t4.q, decode(sign(t8.n-t3.s), -1, t2.n, decode(sign(t2.t-t4.h), 0, t2.h, t5.c))) 
union all
(
select t9.*, rank() over(order by (mod(t9.h+t9.t*t9.q+t9.c+t9.n,2))) r from 
(select 'e' p,0 d,2 t,1 q,1 c, 3 s, 1 h, 3 n from dual
union
select 'e',0,2,1,2, 2, 6, 5  from dual
union
select 'e',0,2,1,2, 4, 2, 3  from dual
union
select 'e',0,2,1,2, 0, 4, 1  from dual
union
select 'e',0,2,1,1, 7, 3, 9  from dual
union
select 'e',0,2,1,1, 9, 8, 3  from dual
union
select 'e',0,2,1,1, 5, 1, 1  from dual
union
select 'e',0,2,1,1, 9, 1, 3  from dual
) t9
)) a
where r = 0 or decode(a.p, 'n', 0, 1) = (
    select  decode(sign(instr(regexp_replace(substr(ch, instr(ch, (select substr(to_char(to_date('01/01/2015', 'dd/mm/yyyy') - 31, 'month'),1,1) from dual)), instr(ch, '?')), '[a-df-z]', 'n'),'e')), 1, 1, 0) t
    from (
    select 'mais quel est le ' || chr(100) || chr(105) || chr(110) || chr(103) || chr(117) || chr(101) || ' qui a écrit ça ?' ch from dual
    )
)
) b 
where mod(b.r, 2) <> 0 or r = 0

 

Additional Hints (Decrypt)

fbhpur

Decryption Key

A|B|C|D|E|F|G|H|I|J|K|L|M
-------------------------
N|O|P|Q|R|S|T|U|V|W|X|Y|Z

(letter above equals below, and vice versa)