The Circle of Pi Mystery Cache

This cache has been archived.

Knagur Green: Due to no response from the CO after the request to maintain or replace the cache, I am archiving it to, stop it showing on the listings and/or to create place for the geocaching community.

The Geocache Maintenance guideline explains a CO's responsibility towards checking and maintaining the cache when problems are reported.

Please note that if geocaches are archived by a reviewer or Geocaching HQ for lack of maintenance, they are not eligible for unarchival. This is explained in the Help Center

If the CO feels that this cache has been archived in error please feel free to contact me within 30 days, via email or message via my profile ,quoting the GC number concerned

Thank you for understanding

Knagur Green
Groundspeak Volunteer Reviewer

More
Hidden : 3/11/2015
Difficulty:
1 out of 5
Terrain:
1.5 out of 5

Size: Size: small (small)

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Geocache Description:


This cache has been placed in celebration of Pi Day 2015.


Geocachers who find a Mystery (Puzzle) cache on 14 March 2015 will earn a special digital souvenir for their profile.

In the year 2015, Pi Day will have special significance on 3/14/15 at 9:26:53 a.m. and p.m., with the date and time representing the first 10 digits of π. That same second will also contain a precise instant corresponding to all of the digits of π.

This cache is NOT at the listed coordinates.  In order to obtain the final coordinates, you will have to solve the following (very easy) puzzle:

Pi to 100 decimal places is: 3.1415926535 8979323846 2643383279 5028841971 6939937510 5820974944 5923078164 0628620899 8628034825 3421170679

S 25º 46.ABC  E 028º 16.DEF

A = 11th decimal digit

B = 32nd decimal digit

C = 50th decimal digit

D = 13th decimal digit

E = 1st decimal digit

F = 9th decimal digit



Or you could just go to S 25º 46.800 E 028º 16.713

Additional Hints (Decrypt)

Orgjrra gjb ebpxf

Decryption Key

A|B|C|D|E|F|G|H|I|J|K|L|M
-------------------------
N|O|P|Q|R|S|T|U|V|W|X|Y|Z

(letter above equals below, and vice versa)


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