Da bi prišli do škatlice bo potrebno rešiti naslednjo uganko:
Na trgatvi so nabirali grozdje in ga zbirali v pütah (brentah). Ko so s trgatvijo končali so opazili, da je v prvi püti en grozd, v drugi 2, v naslednji 4 in tako naprej do 15 püte, v kateri je bilo 2^14 grozdov.
Mimo pride sosed, ki predlaga, da število grozdov v pütah izenačijo z naslednjim postopkom:
Izbral bo 2 püti, seštel število grozdov v obeh, in dal polovico grozdov v prvo, polovico pa v drugo püto. Če je seštevek liho število, bo en grozd pojedel, od ostalih pa jih bo dal polovico v prvo, polovico pa v drugo püto.
Primer: Na začetku izbere 1. in 4. püto, seštevek je 1+8=9, poje en grozd, da 4 nazaj v prvo püto in 4 v četrto püto.Ta postopek lahko ponovi poljubno dostikrat.
Koliko je največje število grozdov, ki jih lahko sosed poje? Zadnje tri števke dobljenega rezultata so: XYZ.
Škatlica se nahaja na koordinatah:
N 46° 34.((XYZ*3/4)-60) E 015° 49.((XYZ+28)/3)
ENG:
To get correct coordinates you'll have to solve the following riddle:
At a grape harvest people were harvesting grapes and putting it in grape containers. When they finished with the harvest, they noticed that in the first container there was one grape, in the second there were two grapes, in the third they were 4 and so on to the 15th container, in which there were 2^14 grapes.
A neighbour passes by and suggests they equalize the number of grapes in each container using the following process:
The neighbour will choose 2 containers, sum the number of grapes in them and put half of the grapes in the first container and half in the second. If the sum is an odd number, he will eat one grape first and then put half in the first container and half in the second.
Example: The neighbour chooses the first and fourth container, the sum is 1+8=9, he eats one grape and then puts 4 in the first container and 4 in the fourth container. The neighbour can repeat the process any number of times.
What's the maximum number of grapes the neighbour can eat? Last three digits of the result are XYZ.
The box is hidden at the following coordinates:
N 46° 34.((XYZ*3/4)-60) E 015° 49.((XYZ+28)/3)
