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U - Dr. Seuss's 115th Birthday Mystery Cache

This cache has been archived.

BAWags75: This cache has gone missing. It has served its time well and now it’s time to go. Thanks for all the finds, messages, and hearts. Archived @ 10:51 AM on 3/29/26.

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Hidden : 12/22/2018
Difficulty:
2 out of 5
Terrain:
1.5 out of 5

Size: Size:   micro (micro)

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Geocache Description:


Dr. Seuss's 115th Birthday Countdown


Congratulations! Today is your day! To solve this puzzle you can think any Think you can wish.

Just go. Go. Go! I don’t care how. You can go by foot. You can go by cow. Solve this puzzle and find the cache now.

Now go get this geocache and then celebrate with a bash!

Dr. Seuss will have a birthday. On March 2, 2019, the children's book author Theodor Seuss Geisel, A.K.A. Dr. Seuss, would become 115 years old.

This geocaching series will consist of fun rhymes, goofy riddles and childhood memories. Every other week for 52 weeks a new geocache will visit another letter of the alphabet. Are you ready to have some fun? Here we go!...

The cache you seek will be easy to find. So just sit back and unwind your mind. Solve the puzzle below and before you know, you will have the prize in your hand...SO LET'S GO!!

DO NOT GO TO THE POSTED COORDINATES. Find the missing numbers in the coordinates below by answering the questions. ALL QUESTIONS PERTAIN ONLY TO THE PUZZLE IN THE PICTURE BELOW

N43° 32.ABC W96° 42.DEF

  1. How many letter a's do you find? Answer multiplied by two equals A
  2. How many letter G's (Not Case Sensitive) do you find? Answer equals B
  3. How many lower-case t's do you find? Answer plus one equals C
  4. How many letter U's (Not Case Sensitive) do you find? Answer equals D
  5. How many letter I's (Not Case Sensitive) do you find? Answer plus two equals E
  6. How many lower-case letter L's do you find? Answer equals F

Additional Hints (Decrypt)

Ng Tebhaq Mreb gnxr gur uvtu ebnq, abg gur ybj ebnq.

Decryption Key

A|B|C|D|E|F|G|H|I|J|K|L|M
-------------------------
N|O|P|Q|R|S|T|U|V|W|X|Y|Z

(letter above equals below, and vice versa)