English version below.
Denne Cache er lagt som en hyldest til Lilliedal (Bo Lilliedal) i anledning af hans geocache fund nummer 10.000 og som en stor tak for hans altid venlige hjælp.
Jeg har personligt været på mange ture, både i ind- og udland, med Lilliedal og det har altid været nogle rigtig hyggelige dage med en masse oplevelser.
Et stort tillykke
Cachen ligger ikke på de opgivne koordinater.
For at løse opgaven og finde slut koordinatet, skal du finde svaret på 5 nemme spørgsmål:
Bemærk at denne cache er udlagt i starten af 2020, så svarene skal findes i årene FØR 2020.
>>> Hvilket år oprettede Lilliedal sin profil? (åååå)
>>> Hvilket år har Lilliedal fundet flest cacher? (åååå)
>>> Hvor mange cacher har Lilliedal fundet i det år han har fundet flest? (xxxx)
>>> Hvilken måned fandt han sin cache nr 100? (mm)
>>> Hvilken måned fandt han sin cache nr 1000? (mm)
De fundne tal omsættes i en
Gade:
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Cachen kan findes her:
N (O-H)(L+G) (B+K)(K+J+E).(T-K)(P-N-H-E)(S-I-N)
E F(Q-K) (L-D)(I+K+J).(H*K)(M-K)(S-I)
29/8-2020 Ny formel, da et af svarene har ændret sig.
N(O-H)(L+G) (B+M)(L+J+E).(T-L)(P-N-H-E)(S-I-N)
E F(L-K+D) (L-D)(I+L+J).(H*M)(M-L)(S-I)
( Tværsum Nord=9 Øst=6 )
ENGLISH:
This Cache was added as a tribute to Lilliedal (Bo Lilliedal) on the occasion of his geocache find number 10,000 and as a big thank you for his always friendly help.
I have personally been on many trips, both in Denmark and abroad, with Lilliedal and it has always been some really nice days with a lot of experiences.
A big congratulations
The cache is not on the given coordinates.
To solve the task and find the coordinate, find the answer to 5 easy questions:
Notice, this cache is released in start of 2020, therefore the answers must be found BEFORE year 2020.
>>> Which year did Lilliedal create his profile? (yyyy)
>>> What year has Lilliedal found the most caches? (yyyy)
>>> How many caches has Lilliedal found in the year he has found the most? (xxxx)
>>> What month did he find his cache # 100? (mm)
>>> What month did he find his cache # 1000? (mm)
Turn the numbers found into a
Gade: <=== Instructions can be found in this cache.
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Cachen can be found here:
N (O-H)(L+G) (B+K)(K+J+E).(T-K)(P-N-H-E)(S-I-N)
E F(Q-K) (L-D)(I+K+J).(H*K)(M-K)(S-I)
8/29-2020 New formula, hence one of the answers has changed.
N(O-H)(L+G) (B+M)(L+J+E).(T-L)(P-N-H-E)(S-I-N)
E F(L-K+D) (L-D)(I+L+J).(H*M)(M-L)(S-I)
Transverse North = 9 East = 6)