Welcome to Concord Township Cemetery! This short multi-cache will take you to two very distinct gravesites which are very different from the markers around them. They also have something in common, along with the final cache. At each site, you will need to find a picture of an animal, and you will use the name of that animal to derive the decimal part of the minutes for the north and west parts of the final coordinates. Note that deep snow will make this cache significantly more difficult to find. During your visit, please be respectful of all who rest here.
Sunrise to sunset caching only!
The final coordinates will be N 41° 40.ABC W 081° 13.DEF
Stage 1 (N 41° 40.453 W 081° 13.247)
Find the very distinct, large family memorial marker at the first stage that sits at the head of a small plot. Only the single-word family name appears on the marker, and the plot in front of it has a border of small rocks and a plastic strip that is slightly above ground. As you are facing the large family marker, you will see a shorter black (or very dark grey) memorial marker sitting just inches away to the left of it. There are two animals etched into the top of this marker on either side. The animals are the same type. You may even find a little statue of the same animal sitting on top of the marker. Since the top of this marker is flat, you may need to brush it off to see the animals if it has snowed recently.
Take the general name of the animal (singular) that you found and add up the values of each letter in its name.
A=1, B=2, C=3, D=4, E=5, F=6, G=7, H=8, I=9, J=10,
K=11, L=12, M=13, N=14, O=15, P=16, Q=17, R=18, S=19, T=20,
U=21, V=22, W=23, X=24, Y=25, Z=26
For example, if the animal were a cat, then the number would be 3 + 1 + 20 = 24.
Once you have this number calculated, ADD 368 to it to get the value for ABC.
Stage 2 (N 41° 40.445 W 081° 13.187)
Once again find a very distinct, large marker at the second stage that has something in common with the family marker from Stage 1. Find the animal on this marker that is not a bird and add up the values of each letter in its name. This animal should have twice as many letters in its name as the animal at Stage 1.
(Just to avoid any possible confusion, this animal does not have a "P" in its name.)
Take that number and ADD 6 to get the value for DEF.