This final Classical Cipher task contains two ciphertexts.
The longer one is encrypted with triple-DES in electronic code book mode.It uses a 128-bit EDE key.The RSA public key cryptosystem has been used to encipher the triple-DES key; this forms the shorter ciphertext.
A shorter message:
F1A4A49BF3589C179C664AAB39942B830965D9F7CC150D004680684982798A5CC3305CD71
F08FD25DB7309
The public exponent is 3247744314306457150247360105787744938443642973757036440140158835550994219878
7392056535628395806452913649
in
decimal and the public modulus is the following 104-digit decimal integer:
82677.47631.03359.36967.54168.06750.25737.88369.58452.63553.00593.19851.28739.04121.
29375.01943.00637.16479.50578.73933.5611
A longer message:
T+DY2FMCBTweYLb6piApSgshc4m8Vb7HhvdgaI5i5tDCYp+0HSfic9VzFW+Kv8bbnMvt
Catn7XFVlitcaDLPSZGqrFcICdqeO/VdNivKkrm6T6q2WL8082+gmRPGCNjbqdiXwYzr
V8ahXo/R+bXkuOBtAQLQUFMOeGZrQDAalzY3ntho7itmzqRFGEsgP264DuFITRYwACk
I5322CaUFdYNRmA/2CHCs1DrSIxdWifQ8KhLHlWx8H23TRe1x6zOp/fTYvIRCG8I54E
voFt6tmHPd9/g4jyWRL0v+n9DUFmi6StGyZMwA8Kbfwzyia5GU3jnv6txeBv6Ozlh9+OGF
SyqZx99A1fodlyPo/d0QWzYaEQleXLyZ5lEEiwHn3CsywQZFrkbik7D1xu9JFmuv6g==
Your task is to decipher the longer message and discover the final coordinates.
How you will do this is up to you, but it will almost certainly be much, much easier to break the
RSA ciphertext by factoring the public modulus than by any other approach.
A small suprise is waiting You at the second part of this task, still this additional challenge is quite easy.
Good luck!
