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A meteorite in Gahanna? Mystery Cache

Hidden : 4/25/2020
Difficulty:
1.5 out of 5
Terrain:
1.5 out of 5

Size: Size:   other (other)

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Geocache Description:


This two part field puzzle will take you to an interesting stone in Mifflin Township Cemetery in Gahanna.

At the posted coordinates you will find the meteorite from the write-up below. You will need to collect the information required to solve for the final location. There you will find the log. No room for anything but the log so bring your own pen

Find: 1: what is the length of the long edge of the concrete base? _________cm = X

2: what is the length of the short edge of the concrete base? ________cm = Y

AB=X-1; CD=Y-7

Final is at: N40 1.3AB W082 52.9CD

 

From The Meteoritical Bulletin, No. 85, 2001 September (https://www.lpi.usra.edu/meteor/docs/mb85.pdf)

Gahanna ∼40º1' N, 82º52' W Franklin County, Ohio, USA Found ∼1950; recognized 1995 February Iron, coarse octahedrite (IAB) A 1201 g iron meteorite was found "40ñ50 years ago" outside of Columbus near Flint Ridge, according to Stephen Holowach, a relative of the finder, although the exact location is not known. Description and classification (G. Huss, ASU; J. Wasson, UCLA): a highly weathered mass, with only the central one-third remaining metallic; moderately shocked, with deformed Widmanst‰tten pattern; contains numerous schreibersite plates ∼1 mm thick and up to ∼1 cm in length; kamacite bandwidth is 2ñ3 mm; bulk metal has Ni = 7.06 wt%, Ga = 85.6 ppm, Ge = 329 ppm, Ir = 1.81 ppm. Specimens: type specimen, 5 g, UCLA; main mass, ASU.

See also: https://www.lpi.usra.edu/meteor/?sea=Ohio&sfor=places&ants=&falls=&valids=&stype=contains&lrec=50&map=ge&browse=&country=All&srt=name&categ=All&mblist=All&rect=&phot=&snew=0&pnt=Normal%20table&code=10842

 

Photo from Jean Jarvis's book 'As It Was In Gahanna and Jefferson Township'.

Additional Hints (Decrypt)

[Cache is not in cemetery, but is nearby]

Decryption Key

A|B|C|D|E|F|G|H|I|J|K|L|M
-------------------------
N|O|P|Q|R|S|T|U|V|W|X|Y|Z

(letter above equals below, and vice versa)